Look at this matrix. Is it invertible? If so, try compute the inverse.

$$ A = \begin{bmatrix} 0 & -1 & 0 \\ 4 & 0 & 5 \\ 3 & 5 & -1 \end{bmatrix} $$
$$ A^{-1}=\begin{bmatrix} \frac{25}{19} & \frac{1}{19} & \frac{5}{19} \\ -1 & 0 & 0 \\ \frac{-20}{19} & \frac{3}{19} & \frac{-4}{19} \end{bmatrix} $$

© 2014 Emanuele Santoro